Hay una fórmula de suma parcial para$$\sum_{x=1}^n x^1 = \frac{n(n+1)}{2}$$ and even one when the exponent of $ x$ is $ 0$: $$\sum_{x=1}^n x^0 = n$$ but I cannot find one for exponent $ - 1$: $$\sum_{x=1}^n x^{-1} = ?$PS
Intenté$$\frac2{n(n+1)},$ $ pero fallé estrepitosamente.